3z/z^2-9-2/3-z

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Solution for 3z/z^2-9-2/3-z equation: 


D( z )

z^2 = 0

z^2 = 0

z^2 = 0

1*z^2 = 0 // : 1

z^2 = 0

z = 0

z in (-oo:0) U (0:+oo)

(3*z)/(z^2)-z-(2/3)-9 = 0

(3*z)/(z^2)-z-2/3-9 = 0

3*z^-1-1*z^1-29/3*z^0 = 0

(3*z^0-1*z^2-29/3*z^1)/(z^1) = 0 // * z^2

z^1*(3*z^0-1*z^2-29/3*z^1) = 0

z^1

(-29/3)*z-z^2+3 = 0

(-29/3)*z-z^2+3 = 0

DELTA = (-29/3)^2-(-1*3*4)

DELTA = 949/9

DELTA > 0

z = ((949/9)^(1/2)-(-29/3))/(-1*2) or z = (-(-29/3)-(949/9)^(1/2))/(-1*2)

z = ((949/9)^(1/2)+29/3)/(-2) or z = (29/3-(949/9)^(1/2))/(-2)

z in { ((949/9)^(1/2)+29/3)/(-2), (29/3-(949/9)^(1/2))/(-2)} 

z in { ((949/9)^(1/2)+29/3)/(-2), (29/3-(949/9)^(1/2))/(-2) }

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